PSYC 355 SPSS HOMEWORK 4 Assignment – ANOVA Papers

PSYC 355 SPSS HOMEWORK 4 Assignment – ANOVA Papers

PSYC 355 SPSS HOMEWORK 4 Assignment – ANOVA Papers

SPSS Homework 4 Instructions

Part One:

Note: For the two-way ANOVA, you will be expected to create a line graph as covered in the SPSS tutorial in the Course Content (and not a boxplot as in the textbook). This applies to future cumulative questions as well.

Green & Salkind: Lesson 26, Exercises 1, 4, 5, 6, 7, and 8

The following helpful tips are numbered to correspond with the exercise number to which they refer (a dash indicates that no tips are needed):

1.Instead of identifying these values on your output, as the text states, please write them into your Word file aswritten answers for #1 a, b, c, and d. (2 pts for output; a-d = 2 pts each)

a. 3×3 Anova was conducted to investigate the effects of reinformecment schedules and arithmetic problem solving performance of second grade students the F value of the main effect was shown as 25.034 the total GPA mean was b. .196 with thec. effect sizeof ________ and d. thep value for the reinforce type main effect is .000

Tests of Between-Subjects Effects

Dependent Variable: Scores on an arithmetic problem-solving test

Source

Type III Sum of Squares

df

Mean Square

F

Sig.

Partial Eta Squared

Corrected Model

1927.455a

5

385.491

19.662

.000

.621

Intercept

56204.182

1

56204.182

2866.674

.000

.979

schedule

490.909

1

490.909

25.039

.000

.294

reinfor

1249.182

2

624.591

31.857

.000

.515

schedule * reinfor

187.364

2

93.682

4.778

.012

.137

Error

1176.364

60

19.606

Total

59308.000

66

Corrected Total

3103.818

65

a. R Squared = .621 (Adjusted R Squared = .589)

4.Produce a line graph instead of a boxplot for this problem. Follow directions in course SPSS tutorial for setting up a line graph. (2 pts) PSYC 355 SPSS HOMEWORK 4 Assignment – ANOVA Papers.

5.Conduct a two way ANOVA to evaluat difference among the groups, according to gender and disability status of the child, in the amount of time fathers spent playing with their children (2 pts)

Between-Subjects Factors

Value Label

N

Disability status of the child

1

Typically Developing

20

2

Physical Disability

20

3

Mental Retardation

20

Gender of Child

1

Male

29

2

Female

31

Descriptive Statistics

Dependent Variable: play

Disability status of the child

Gender of Child

Mean

Std. Deviation

N

Typically Developing

Male

7.30

1.829

10

Female

6.80

2.201

10

Total

7.05

1.986

20

Physical Disability

Male

3.00

1.563

10

Female

3.40

1.897

10

Total

3.20

1.704

20

Mental Retardation

Male

3.22

1.716

9

Female

4.00

1.612

11

Total

3.65

1.663

20

Total

Male

4.55

2.613

29

Female

4.71

2.369

31

Total

4.63

2.470

60

Levene’s Test of Equality of Error Variancesa

Dependent Variable: play

F

df1

df2

Sig.

.427

5

54

.828

Tests the null hypothesis that the error variance of the dependent variable is equal across groups.

a. Design: Intercept + disable + gender + disable * gender

Tests of Between-Subjects Effects

Dependent Variable: play

Source

Type III Sum of Squares

df

Mean Square

F

Sig.

Partial Eta Squared

Corrected Model

182.278a

5

36.456

11.081

.000

.506

Intercept

1276.571

1

1276.571

388.025

.000

.878

disable

178.579

2

89.289

27.140

.000

.501

gender

.763

1

.763

.232

.632

.004

disable * gender

4.294

2

2.147

.653

.525

.024

Error

177.656

54

3.290

Total

1648.000

60

Corrected Total

359.933

59

a. R Squared = .506 (Adjusted R Squared = .461)

Estimates

Dependent Variable: play

Disability status of the child

Mean

Std. Error

95% Confidence Interval

Lower Bound

Upper Bound

Typically Developing

7.050

.406

6.237

7.863

Physical Disability

3.200

.406

2.387

4.013

Mental Retardation

3.611

.408

2.794

4.428

Pairwise Comparisons

Dependent Variable: play

(I) Disability status of the child

(J) Disability status of the child

Mean Difference (I-J)

Std. Error

Sig.b

95% Confidence Interval for Differenceb

Lower Bound

Upper Bound

Typically Developing

Physical Disability

3.850*

.574

.000

2.700

5.000

Mental Retardation

3.439*

.575

.000

2.286

4.592

Physical Disability

Typically Developing

-3.850*

.574

.000

-5.000

-2.700

Mental Retardation

-.411

.575

.478

-1.564

.742

Mental Retardation

Typically Developing

-3.439*

.575

.000

-4.592

-2.286

Physical Disability

.411

.575

.478

-.742

1.564

Based on estimated marginal means

*. The mean difference is significant at the .05 level.

b. Adjustment for multiple comparisons: Least Significant Difference (equivalent to no adjustments).

6.I would use a three way comparison I would say by looking at the graph and data the data shows some significance and in order to maintain the intergrity of the study and data a three way comparison would be used.(2 pts) PSYC 355 SPSS HOMEWORK 4 Assignment – ANOVA Papers.

7.All homework “Results sections” should follow the example given in the Course Content document “Writing Results of Statistical Tests in APA Format” (note: you do not have to refer to a figure). (2 pts)

Tests of Between-Subjects Effects

Dependent Variable: play

Source

Type III Sum of Squares

df

Mean Square

F

Sig.

Partial Eta Squared

Corrected Model

182.278a

5

36.456

11.081

.000

.506

Intercept

1276.571

1

1276.571

388.025

.000

.878

disable

178.579

2

89.289

27.140

.000

.501

gender

.763

1

.763

.232

.632

.004

disable * gender

4.294

2

2.147

.653

.525

.024

Error

177.656

54

3.290

Total

1648.000

60

Corrected Total

359.933

59

a. R Squared = .506 (Adjusted R Squared = .461)

A 3×3 Anova was conducted to determine the effects of three disability conditions (mental retardation, typical development, and physical disability) and two genders. F (1,54) = 27.140, p<.001 =

= .50

8.Produce a line graph instead of a boxplot for this problem. Follow directions in course SPSS tutorial for setting up a line graph. (2 pts) PSYC 355 SPSS HOMEWORK 4 Assignment – ANOVA Papers.

Part Two:

1.A health psychologist is interested in the effects of exercise on stress in people who regularly exercise. Specifically, she is interested in the type of exercise as well as the time of day that the individual exercises. She recruits participants from a local health club who regularly participate in one of three types of exercise: swimming, aerobics, and tennis. She further divides these participants by whether they exercise in the morning or the evening. She then administers a questionnaire to each individual assessing their self-reported stress level. (HIGHER SCORE = HIGHER STRESS).Conduct a two-way ANOVA to analyze these data. Use Tukey’s test in order to conduct any necessary post hoc analyses if there are significant main effects. You do not have to follow up on significant interactions at this time.

The steps will be the same as the ones you have been practicing in Part One of the assignment—the only difference is that you are now responsible for creating the data file as well. Remember to name and define your variables under the “Variable View,” then return to the “Data View” to enter the data. (2 pts for output, – 1 pt if no post hoc)

Morning

Swimming

Aerobics

Tennis

10

16

12

16

9

19

21

16

18

17

21

18

14

Evening

14

13

8

12

12

17

12

14

9

10

12

15

19

14

2.Write an APA-style results section describing the outcome. All homework “Results sections” should follow the example given in the Course Content document “Writing Results of Statistical Tests in APA Format” (note: you do not have to refer to a figure). For the two-way ANOVA, be sure to include statistical statements concerning the F ratios and p values for both main effects and the interaction, and interpretation statements about all 3 of these effects. (2 pts)

3.Is there a significant interaction effect? (2 pts)

4.Based on your results, is there one type of exercise that seems more effective in reducing stress than the others? Remember that higher scores = higher stress. (2 pts)

This assignment is due by 11:59 p.m. (ET) on Monday of Module/Week 4.

Part Three: Cumulative Homework

1. An investigator in child development research is studying the development of object permanence – the understanding that an object still exists even if its out of sight. She tests three groups of infants – ten who are 9 months old, 8 who are 12 months old, and 10 who are 15 months old. She presents each of the infants with 10 trials. On each trial, a toy is first shown to the child and then covered with a piece of cloth. The infant demonstrates object permanence if he or she looks for the object when it’s covered. Each infant is given a score for the number of trials (out of 10) on which he or she shows object permanence. Is there a significant difference between the groups on demonstrations of object permanence? Choose the correct test to analyze this question, set up the SPSS file, and run the analysis. Follow the directions under the table below.

9 Months

8, 3, 4, 6, 5, 4, 9, 2, 0, 1

12 Months

10, 5, 6, 7, 6, 5, 10, 3

15 Months

10, 8, 9, 9, 8, 7, 9, 6, 6, 8

a)Paste appropriate SPSS output. (2 pts)

b)Paste appropriate SPSS graph. (2 pts)

c)Write an APA-style results section describing the outcome. All homework “Results sections” should follow the example given in the Course Content document “Writing Results of Statistical Tests in APA Format” (note: you do not have to refer to a figure). (2 pts) PSYC 355 SPSS HOMEWORK 4 Assignment – ANOVA Papers

2.A researcher wanted to investigate whether there was a difference in satisfaction ratings in an assisted living facility between residents who had a pet with them vs. those who did not have a pet. She administered a scale asking them to rate their overall satisfaction with the facility. Did having a pet have an impact on the residents’ overall satisfaction levels? Choose the correct test to analyze this question, set up the SPSS file, and run the analysis. Follow the directions under the table below (on next page).