PSYC 355 SPSS HOMEWORK 4 Assignment – ANOVA Papers
PSYC 355 SPSS HOMEWORK 4 Assignment – ANOVA PapersSPSS Homework 4 Instructions
Part One:
Note: For the twoway ANOVA, you will be expected to create a line graph as covered in the SPSS tutorial in the Course Content (and not a boxplot as in the textbook). This applies to future cumulative questions as well.
Green & Salkind: Lesson 26, Exercises 1, 4, 5, 6, 7, and 8
The following helpful tips are numbered to correspond with the exercise number to which they refer (a dash indicates that no tips are needed):
1.Instead of identifying these values on your output, as the text states, please write them into your Word file aswritten answers for #1 a, b, c, and d. (2 pts for output; ad = 2 pts each)
a. 3×3 Anova was conducted to investigate the effects of reinformecment schedules and arithmetic problem solving performance of second grade students the F value of the main effect was shown as 25.034 the total GPA mean was b. .196 with thec. effect sizeof ________ and d. thep value for the reinforce type main effect is .000
Tests of BetweenSubjects Effects 

Dependent Variable: Scores on an arithmetic problemsolving test 

Source 
Type III Sum of Squares 
df 
Mean Square 
F 
Sig. 
Partial Eta Squared 
Corrected Model 
1927.455a 
5 
385.491 
19.662 
.000 
.621 
Intercept 
56204.182 
1 
56204.182 
2866.674 
.000 
.979 
schedule 
490.909 
1 
490.909 
25.039 
.000 
.294 
reinfor 
1249.182 
2 
624.591 
31.857 
.000 
.515 
schedule * reinfor 
187.364 
2 
93.682 
4.778 
.012 
.137 
Error 
1176.364 
60 
19.606 

Total 
59308.000 
66 

Corrected Total 
3103.818 
65 

a. R Squared = .621 (Adjusted R Squared = .589) 
4.Produce a line graph instead of a boxplot for this problem. Follow directions in course SPSS tutorial for setting up a line graph. (2 pts) PSYC 355 SPSS HOMEWORK 4 Assignment – ANOVA Papers.
5.Conduct a two way ANOVA to evaluat difference among the groups, according to gender and disability status of the child, in the amount of time fathers spent playing with their children (2 pts)
BetweenSubjects Factors 

Value Label 
N 

Disability status of the child 
1 
Typically Developing 
20 
2 
Physical Disability 
20 

3 
Mental Retardation 
20 

Gender of Child 
1 
Male 
29 
2 
Female 
31 
Descriptive Statistics 

Dependent Variable: play 

Disability status of the child 
Gender of Child 
Mean 
Std. Deviation 
N 
Typically Developing 
Male 
7.30 
1.829 
10 
Female 
6.80 
2.201 
10 

Total 
7.05 
1.986 
20 

Physical Disability 
Male 
3.00 
1.563 
10 
Female 
3.40 
1.897 
10 

Total 
3.20 
1.704 
20 

Mental Retardation 
Male 
3.22 
1.716 
9 
Female 
4.00 
1.612 
11 

Total 
3.65 
1.663 
20 

Total 
Male 
4.55 
2.613 
29 
Female 
4.71 
2.369 
31 

Total 
4.63 
2.470 
60 
Levene’s Test of Equality of Error Variancesa 

Dependent Variable: play 

F 
df1 
df2 
Sig. 
.427 
5 
54 
.828 
Tests the null hypothesis that the error variance of the dependent variable is equal across groups. 

a. Design: Intercept + disable + gender + disable * gender 
Tests of BetweenSubjects Effects 

Dependent Variable: play 

Source 
Type III Sum of Squares 
df 
Mean Square 
F 
Sig. 
Partial Eta Squared 
Corrected Model 
182.278a 
5 
36.456 
11.081 
.000 
.506 
Intercept 
1276.571 
1 
1276.571 
388.025 
.000 
.878 
disable 
178.579 
2 
89.289 
27.140 
.000 
.501 
gender 
.763 
1 
.763 
.232 
.632 
.004 
disable * gender 
4.294 
2 
2.147 
.653 
.525 
.024 
Error 
177.656 
54 
3.290 

Total 
1648.000 
60 

Corrected Total 
359.933 
59 

a. R Squared = .506 (Adjusted R Squared = .461) 
Estimates 

Dependent Variable: play 

Disability status of the child 
Mean 
Std. Error 
95% Confidence Interval 

Lower Bound 
Upper Bound 

Typically Developing 
7.050 
.406 
6.237 
7.863 
Physical Disability 
3.200 
.406 
2.387 
4.013 
Mental Retardation 
3.611 
.408 
2.794 
4.428 
Pairwise Comparisons 

Dependent Variable: play 

(I) Disability status of the child 
(J) Disability status of the child 
Mean Difference (IJ) 
Std. Error 
Sig.b 
95% Confidence Interval for Differenceb 

Lower Bound 
Upper Bound 

Typically Developing 
Physical Disability 
3.850* 
.574 
.000 
2.700 
5.000 
Mental Retardation 
3.439* 
.575 
.000 
2.286 
4.592 

Physical Disability 
Typically Developing 
3.850* 
.574 
.000 
5.000 
2.700 
Mental Retardation 
.411 
.575 
.478 
1.564 
.742 

Mental Retardation 
Typically Developing 
3.439* 
.575 
.000 
4.592 
2.286 
Physical Disability 
.411 
.575 
.478 
.742 
1.564 

Based on estimated marginal means 

*. The mean difference is significant at the .05 level. 

b. Adjustment for multiple comparisons: Least Significant Difference (equivalent to no adjustments). 
6.I would use a three way comparison I would say by looking at the graph and data the data shows some significance and in order to maintain the intergrity of the study and data a three way comparison would be used.(2 pts) PSYC 355 SPSS HOMEWORK 4 Assignment – ANOVA Papers.
7.All homework “Results sections” should follow the example given in the Course Content document “Writing Results of Statistical Tests in APA Format” (note: you do not have to refer to a figure). (2 pts)
Tests of BetweenSubjects Effects 

Dependent Variable: play 

Source 
Type III Sum of Squares 
df 
Mean Square 
F 
Sig. 
Partial Eta Squared 
Corrected Model 
182.278a 
5 
36.456 
11.081 
.000 
.506 
Intercept 
1276.571 
1 
1276.571 
388.025 
.000 
.878 
disable 
178.579 
2 
89.289 
27.140 
.000 
.501 
gender 
.763 
1 
.763 
.232 
.632 
.004 
disable * gender 
4.294 
2 
2.147 
.653 
.525 
.024 
Error 
177.656 
54 
3.290 

Total 
1648.000 
60 

Corrected Total 
359.933 
59 

a. R Squared = .506 (Adjusted R Squared = .461) 
A 3×3 Anova was conducted to determine the effects of three disability conditions (mental retardation, typical development, and physical disability) and two genders. F (1,54) = 27.140, p<.001 =
= .50
8.Produce a line graph instead of a boxplot for this problem. Follow directions in course SPSS tutorial for setting up a line graph. (2 pts) PSYC 355 SPSS HOMEWORK 4 Assignment – ANOVA Papers.
Part Two:
1.A health psychologist is interested in the effects of exercise on stress in people who regularly exercise. Specifically, she is interested in the type of exercise as well as the time of day that the individual exercises. She recruits participants from a local health club who regularly participate in one of three types of exercise: swimming, aerobics, and tennis. She further divides these participants by whether they exercise in the morning or the evening. She then administers a questionnaire to each individual assessing their selfreported stress level. (HIGHER SCORE = HIGHER STRESS).Conduct a twoway ANOVA to analyze these data. Use Tukey’s test in order to conduct any necessary post hoc analyses if there are significant main effects. You do not have to follow up on significant interactions at this time.
The steps will be the same as the ones you have been practicing in Part One of the assignment—the only difference is that you are now responsible for creating the data file as well. Remember to name and define your variables under the “Variable View,” then return to the “Data View” to enter the data. (2 pts for output, – 1 pt if no post hoc)
Morning 
Swimming 
Aerobics 
Tennis 
10 16 12 16 9 
19 21 16 18 
17 21 18 14 

Evening 
14 13 8 12 12 
17 12 14 9 10 
12 15 19 14 
2.Write an APAstyle results section describing the outcome. All homework “Results sections” should follow the example given in the Course Content document “Writing Results of Statistical Tests in APA Format” (note: you do not have to refer to a figure). For the twoway ANOVA, be sure to include statistical statements concerning the F ratios and p values for both main effects and the interaction, and interpretation statements about all 3 of these effects. (2 pts)
3.Is there a significant interaction effect? (2 pts)
4.Based on your results, is there one type of exercise that seems more effective in reducing stress than the others? Remember that higher scores = higher stress. (2 pts)
This assignment is due by 11:59 p.m. (ET) on Monday of Module/Week 4.
Part Three: Cumulative Homework
1. An investigator in child development research is studying the development of object permanence – the understanding that an object still exists even if its out of sight. She tests three groups of infants – ten who are 9 months old, 8 who are 12 months old, and 10 who are 15 months old. She presents each of the infants with 10 trials. On each trial, a toy is first shown to the child and then covered with a piece of cloth. The infant demonstrates object permanence if he or she looks for the object when it’s covered. Each infant is given a score for the number of trials (out of 10) on which he or she shows object permanence. Is there a significant difference between the groups on demonstrations of object permanence? Choose the correct test to analyze this question, set up the SPSS file, and run the analysis. Follow the directions under the table below.
9 Months
8, 3, 4, 6, 5, 4, 9, 2, 0, 1
12 Months
10, 5, 6, 7, 6, 5, 10, 3
15 Months
10, 8, 9, 9, 8, 7, 9, 6, 6, 8
a)Paste appropriate SPSS output. (2 pts)
b)Paste appropriate SPSS graph. (2 pts)
c)Write an APAstyle results section describing the outcome. All homework “Results sections” should follow the example given in the Course Content document “Writing Results of Statistical Tests in APA Format” (note: you do not have to refer to a figure). (2 pts) PSYC 355 SPSS HOMEWORK 4 Assignment – ANOVA Papers
2.A researcher wanted to investigate whether there was a difference in satisfaction ratings in an assisted living facility between residents who had a pet with them vs. those who did not have a pet. She administered a scale asking them to rate their overall satisfaction with the facility. Did having a pet have an impact on the residents’ overall satisfaction levels? Choose the correct test to analyze this question, set up the SPSS file, and run the analysis. Follow the directions under the table below (on next page).